An engine of mass 200 tonnes is pulling a train of 10 carriages, each of mass 60 tonnes. The engine is exerting its maximum pull of 2 x 10^5 N when the train is moving at a constant speed of 36 km/hr. Due to the disengagement of the coupling between the 5 th and 6 th carriages, the rear five carriages get separated and the engine hauls the first five carriages exerting the same pull. Assuming the tractive resistance is proportional to the weight, find how far ahead the front half of the train is when the rear half comes to rest?

Question

Arun · Answer

Mass of the engine, m = 60 tonnes = 60000 kg
Radius of the arc, r = 200 m
Velocity of the train, v = 36 km/hr
To find:
Force exerted towards the center = ?
Solution:
First, km/hr is to be converted into m/s

Thereby,
Force exerted on the rails towards the center is given by the formula given below,

F = 30000 N

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