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An electron is continuously accelerated in a vacuum tubeby applying a potential difference. If the de Broglie wavelength is decreased by 10%, the change in kinetic energy of the electron is

smitha , 10 Years ago
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anser 1 Answers
Sumit Majumdar

Last Activity: 10 Years ago

Dear student,

We have the equation being given by:
[\lambda =\frac{h}{\sqrt{2mK.E}}=\frac{h}{\sqrt{2m}}\left ( K.E \right )^{-\frac{1}{2}}]
So, we get:
[\left (\frac{d\lambda}{\lambda} \right ) =\frac{-1}{2}}\left (\frac{dK.E.}{K.E} \right )]
So,
[\left (\frac{dK.E.}{K.E.} \right )\times 100 =2\left (\frac{d\lambda.}{\lambda} \right )\times 100=20%]
Regards
Sumit

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