Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

An electron is continuously accelerated in a vacuum tube by applying a potential difference. If the de Broglie wavelength is decreased by 10%, the change in kinetic energy of the electron is

An electron is continuously accelerated in a vacuum tube  by applying a potential difference. If the de Broglie wavelength is decreased by 10%, the change in kinetic energy of the electron is

Grade:

1 Answers

Sumit Majumdar IIT Delhi
askIITians Faculty 137 Points
7 years ago
Dear student,

We have the equation being given by:
[\lambda =\frac{h}{\sqrt{2mK.E}}=\frac{h}{\sqrt{2m}}\left ( K.E \right )^{-\frac{1}{2}}]
So, we get:
[\left (\frac{d\lambda}{\lambda} \right ) =\frac{-1}{2}}\left (\frac{dK.E.}{K.E} \right )]
So,
[\left (\frac{dK.E.}{K.E.} \right )\times 100 =2\left (\frac{d\lambda.}{\lambda} \right )\times 100=20%]
Regards
Sumit

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free