An electron beam of 10Kev energy is to be bombarded inside a solenoid of radius 10cm and 120 turns per meter. If the beam is not to touch the walls of the solenoid the maximum current through the wire should .

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Arun · Answer

q = [(ΔϕΔt)1 / R]Δt q = [μ0nNπr^2Δi/Δt]1/RΔt q = [4×10^−7×2×10^4×100×π×(10^−2)^2×(40.05)] 1 /10π^2×0.05 q = [ 2512 x 10-7+4 -4 x 4 / 0.05] 1/10 x 3.14 x 3.14 x 0.05 q = [ 2.5 x 10^-4 x 4/ 0.05 ] x 1/ 98.59 x 0.05 q = 32 μC Thus the total charge flowing through the coil during this time is q = 32 μC Hope it helps

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An electron beam of 10Kev energy is to be bombarded inside a solenoid of radius 10cm and 120 turns per meter. If the beam is not to touch the walls of the solenoid the maximum current through the wire should .

An electron beam of 10Kev energy is to be bombarded inside a solenoid of radius 10cm and 120 turns per meter. If the beam is not to touch the walls of the solenoid the maximum current through the wire should .

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An electron beam of 10Kev energy is to be bombarded inside a solenoid of radius 10cm and 120 turns per meter. If the beam is not to touch the walls of the solenoid the maximum current through the wire should .

An electron beam of 10Kev energy is to be bombarded inside a solenoid of radius 10cm and 120 turns per meter. If the beam is not to touch the walls of the solenoid the maximum current through the wire should .

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