ABCD is a trapezium. (AB || DC) . P and Q are two points on AD and BC respectively. AP : PD = BQ : QC. Prove that PQ || DC.

Question

Arun · Answer

AB and CD are parallel lines. We are given P and Q are mid point of AD and BC respectively. Line AD and Line BC are segmented equally by line PQ which is drawn between parallel lines AB and CD. Hence lines AB, CD and PQ are parallel to each other.

Sayantan Garai · Answer

It is not given they are the mid points.

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ABCD is a trapezium. (AB || DC) . P and Q are two points on AD and BC respectively. AP : PD = BQ : QC. Prove that PQ || DC.

ABCD is a trapezium. (AB || DC) .
P and Q are two points on AD and BC respectively. AP : PD = BQ : QC.
Prove that PQ || DC.

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ABCD is a trapezium. (AB || DC) . P and Q are two points on AD and BC respectively. AP : PD = BQ : QC. Prove that PQ || DC.

ABCD is a trapezium. (AB || DC) . P and Q are two points on AD and BC respectively. AP : PD = BQ : QC. Prove that PQ || DC.

2 Answers

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ABCD is a trapezium. (AB || DC) .
P and Q are two points on AD and BC respectively. AP : PD = BQ : QC.
Prove that PQ || DC.