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Grade 12th passDiscuss with Askiitians Tutors

A uniform chain has a mass M and length L.It is placed on a frictionless table with length lo hanging over the edge .The chain begins to slide down .Then the speed v with which the end slide down from the edge is given by
1.{g(L+lo)/L}1/2
2.{g(L-lo)/L}1/2
3.{g(L2-lo2)/L}1/2

Profile image of Kaushki
8 Years agoGrade 12th pass
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1 Answer

Profile image of Arun
8 Years ago
Dear student
 
MgL/2 - Mg (lo)² /2L = ½ * M *v²
 
 
v = \large \sqrt[g(L)2 - (lo)² /L ]
 
 
Regards
Arun (askIITians forum expert)