A solution is 0.1MBa(No3) 2 & 0.1Msr(No3)2. If solid Na2cro4 is added to the solution. What is [Ba] when srcro4 begins to precipitate?? Ksp of Bacro4 is 1.2×10^(-10) , Ksp of srcro4 is 3.5×10^(-5).

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B Gowreeswaramma · Answer

[Ba] = ksp / [cro4], [cro4=ksp/[ Sr] i. e., 3.5 *10^(-5) /0.1 , =3.5 *0.0001 so Ba =3.7*10^(-7)approximatelya

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A solution is 0.1MBa(No3) 2 & 0.1Msr(No3)2. If solid Na2cro4 is added to the solution. What is [Ba] when srcro4 begins to precipitate?? Ksp of Bacro4 is 1.2×10^(-10) , Ksp of srcro4 is 3.5×10^(-5).

A solution is 0.1MBa(No3) 2 & 0.1Msr(No3)2. If solid Na2cro4 is added to the solution. What is [Ba] when srcro4 begins to precipitate?? Ksp of Bacro4 is 1.2×10^(-10) , Ksp of srcro4 is 3.5×10^(-5).

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A solution is 0.1MBa(No3) 2 & 0.1Msr(No3)2. If solid Na2cro4 is added to the solution. What is [Ba] when srcro4 begins to precipitate?? Ksp of Bacro4 is 1.2×10^(-10) , Ksp of srcro4 is 3.5×10^(-5).

A solution is 0.1MBa(No3) 2 & 0.1Msr(No3)2. If solid Na2cro4 is added to the solution. What is [Ba] when srcro4 begins to precipitate?? Ksp of Bacro4 is 1.2×10^(-10) , Ksp of srcro4 is 3.5×10^(-5).

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