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`        A projectile is projected from the ground at t=0 with initial speed u at angle theta with horizontal `
4 months ago

Arun
23769 Points
```							See we need to find the time at which initial velocity vector is perpendicular to velocity vector at that time , initially the angle is theta  ( I'm considering the angle as @ )resolving initial velocity vector we get,   usin@j^ + ucos@i^Now at any time t velocity vector of projectile is given by formula, V vector = ucos@i^ + (usin@ - gt)j^We have initial and final required velocity vector, since it is given they are perpendicular their dot product must be 0 ⇒ u^2cos^2@ + u^2sin^2@ - gtusin@ = 0= u^2 - gtusin@ = 0⇒ t= u/gsin@
```
4 months ago
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• Previous Year Exam Questions