A parallel plate capacitor has plates of area a and separation d and is charged to a potential difference v. The charging battery is then disconnected and the plates are pulled apart until their separation is 2d. What is the work require to separate the plates

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aditya mittal · Answer

Hi Ashutosh rout Here is your answer Work done W = U f &minus; U i U i = 1 2 C V 0 2 and U f = 1 2 ( C ) 3 . ( 3 V 0 ) 2 = 3 &times; 1 2 C V 0 2 hope this will help you approved the answer So W = &epsilon; 0 A V 0 2 d Hhhiope

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A parallel plate capacitor has plates of area a and separation d and is charged to a potential difference v. The charging battery is then disconnected and the plates are pulled apart until their separation is 2d. What is the work require to separate the plates

A parallel plate capacitor has plates of area a and separation d and is charged to a potential difference v. The charging battery is then disconnected and the plates are pulled apart until their separation is 2d. What is the work require to separate the plates

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A parallel plate capacitor has plates of area a and separation d and is charged to a potential difference v. The charging battery is then disconnected and the plates are pulled apart until their separation is 2d. What is the work require to separate the plates

A parallel plate capacitor has plates of area a and separation d and is charged to a potential difference v. The charging battery is then disconnected and the plates are pulled apart until their separation is 2d. What is the work require to separate the plates

1 Answers

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