Guest

Two particles of masses ma and m2 in projectile motion have velocities vectors v 1 2 respectively at time t=0. They collide at time t 0 . Their velocities become v' 1 and v' 2 at time 2t 0 while still moving in air. The value of |(m 1 v' 1 + m 2 v' 2 ) - (m 1 v 1 + m 2 v 2 )| is: (A) Zero (B) (m 1 + m 2 ) gt 0 (C) 2(m 1 + m 2 ) gt 0 (D) 1/2(m 1 + m 2 ) gt 0

Two particles of masses ma and m2 in projectile motion have velocities vectors v1 <  v2 respectively at time t=0. They collide at time t0. Their velocities become  v'1 and v'2 at time 2t0 while still moving in air. The value of |(m1 v'1+ m2v') - (m1v1+ m2v)| is: 
(A) Zero 
(B) (m1 + m2) gt0
(C) 2(m1 + m2) gt0
(D) 1/2(m1 + m2) gt0 

Grade:

0 Answers

No Answer Yet!

ASK QUESTION

Get your questions answered by the expert for free