THE NUMBER OF SOLUTIONS OF THE EQUATION

Z^2 + Z' = 0 IS -------

A) 4

B)3

C)2

D)1

Put z = x + iy

and z'' = x - iy

(x + iy)^2 + x - iy = 0

x^2 - y^2 + 2xyi + x - iy = 0

(x^2 - y^2 + x) + i(2xy - y) = 0

1) 2xy - y = 0

    y(2x - 1) = 0

 y = 0 , x = 1/2

2) x^2 - y^2 + x= 0

    at x = 1/2 y= +root3/2, -root3/2

    at y = 0 x = 0, -1

Therefore answer shoulbe (a) 4 solutions.

PLZ  APPROVE 

Dear frnd!

2) x^2 - y^2 + x= 0