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What is the value of tan15.
let tan15=x,tan30=sqrt(1/3),
2x/(1-x2)=tan30
use the formula tan A-B
a=45 and b= 30
i prefer if you solve urself..
Dear preet,
tan 15=tan(45-30)
=(tan 45-tan 30)/(1+tan 45*tan 30)
[As tan(A-B)=(tan A-tan B)/(1+tan A*tan B)}
giving value : tan 45=1 and tan 30=1/underroot 3
we get,tan 15=({underroot 3}-1)/({underroot 3}+1)
=1.732-1/1.732+1
=0.732/2.732
=0.26794
=0.268.------>> ANS:
0.2679
tan(45-30)= root3 - 1 / root3 + 1= [root3-1]^2 / 2 = 2-root3 ANS.
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