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Q. two 1g carbon disks 1.00cm apart have opposite charges of equal magnitude such that there is a 10 -5 N force between them .the ratio of excess electrons to total atoms on negatively charged disks is:
Hi Rahul, 1g ......... 1/14 * 6.023*10^23 atoms F= 9*10^9*q2/r2 1/9*10-5*10-9*10-4=q2 q=1/3 *10-9 no of electrons on each carbon is 1/(3*1.609) *1010 ratio= 14/(3*1.6*6.023) * 10-13
Hi Rahul,
1g ......... 1/14 * 6.023*10^23 atoms
F= 9*10^9*q2/r2
1/9*10-5*10-9*10-4=q2
q=1/3 *10-9
no of electrons on each carbon is 1/(3*1.609) *1010
ratio= 14/(3*1.6*6.023) * 10-13
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