Let w be a cube root of unity which is not equal to 1. Then the number of distinct elements in the set
{(1+w+w2+w3+...+wn)^m : m,n=1,2,3,...} is ?

Question

Let w be a cube root of unity which is not equal to 1. Then the number of distinct elements in the set {(1+w+w2+w3+...+wn)^m : m,n=1,2,3,...} is ?

Nishant Vora · Answer

Take m, n = 1,2,3 only

for other values the same thing will repeat

So total nine cases will be formed (3*3)

Now out of these nine few may be duplicate so you need to remove then

I hope its clear to you

thanks

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Guest

Let w be a cube root of unity which is not equal to 1. Then the number of distinct elements in the set {(1+w+w2+w3+...+wn)^m : m,n=1,2,3,...} is ?

Let w be a cube root of unity which is not equal to 1. Then the number of distinct elements in the set
{(1+w+w2+w3+...+wn)^m : m,n=1,2,3,...} is ?

1 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Discuss with Askiitians Tutors

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Guest

IIT JEE Courses

One Year IIT Programme

Two Year IIT Programme

Crash Course

NEET Courses

One Year NEET Programme

Two Year NEET Programme

One to One

School Board

Live Online classes

Class 11 & 12

Class 9 & 10

Class 6, 7 & 8

Test Series

JEE test series

NEET test series

C.B.S.E test series

Complete Self Study Packages

FULL COURSE

For class 12th

For class 11th

Let w be a cube root of unity which is not equal to 1. Then the number of distinct elements in the set {(1+w+w2+w3+...+wn)^m : m,n=1,2,3,...} is ?

Let w be a cube root of unity which is not equal to 1. Then the number of distinct elements in the set {(1+w+w2+w3+...+wn)^m : m,n=1,2,3,...} is ?

1 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Discuss with Askiitians Tutors

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship

Let w be a cube root of unity which is not equal to 1. Then the number of distinct elements in the set
{(1+w+w2+w3+...+wn)^m : m,n=1,2,3,...} is ?