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the point on x-axis which is equidistant from the point (2,-1,4)(-4,3,10)
a point on x axis implies y=0 and z=0
so taking the distance formula,
(x-2)2+12+42 = (x+4)2+32+102
so, -4x+4+1+16=8x+16+9+100
solving for x, 12x=104
x=104/12= 26/3
so the point is (26/3, 0, 0)
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