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# 3 dices are rolled together what is the probability of getting different nos on the 3 dices??????? in what respect does this ques is diff from prev one? give the solutions also>>>>>>>>>>

jitender lakhanpal
62 Points
9 years ago

Dear Nivi,

sample space = 63

and the number of favourable cases can be visualised as arranging 6 different objects in 3 different places

this is same as the definition of permutation so the number of favourable cases is P(6,3)=6*5*4

so the probability = (6*5*4)/216 = 5/9

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jitender

New layer...
ayush jain
30 Points
9 years ago

n(e)=6*5*4=120

n(s)=6*6*6=216

than probility=120/216=5/9.....................(ans)