3 dices are rolled together what is the probability of getting different nos on the 3 dices???????in what respect does this ques is diff from prev one?give the solutions also>>>>>>>>>>

Dear Nivi,

sample space = 6³

and the number of favourable cases can be visualised as arranging 6 different objects in 3 different places 

this is same as the definition of permutation so the number of favourable cases is P(6,3)=6*5*4

so the probability = (6*5*4)/216 = 5/9

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Approved

n(e)=6*5*4=120

n(s)=6*6*6=216

than probility=120/216=5/9.....................(ans)

Approved