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Dear Nivi,
sample space = 63
and the number of favourable cases can be visualised as arranging 6 different objects in 3 different places
this is same as the definition of permutation so the number of favourable cases is P(6,3)=6*5*4
so the probability = (6*5*4)/216 = 5/9
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jitender
n(e)=6*5*4=120
n(s)=6*6*6=216
than probility=120/216=5/9.....................(ans)
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