the sides of a triangle are 2x-y+5=0,x+y-5=0,x-2y-5=0 sum of tangents of its interior angles is ______________________

At one vertex, 2x-y+5=0 and x+y-5=0 meet so by using simultaneous equations x=0 and y=5. Thus the co-ordinates of that vertex is [0,5]. By using this method the other vertex wud be [-5,-5] and [5.,0]. Now find the length of each side by distance formula and the length will be sqrt125,sqrt125 and sqrt50. Now, draw a perpendicular line from a vertex to the side of length sqrt50. The perp. line wud bisect that line as the. Now u can find the tangents of the angles.

Dear Archu,

At one vertex, 2x-y+5=0 and x+y-5=0 meet so by using simultaneous equations x=0 and y=5. Thus the co-ordinates of that vertex is [0,5]. By using this method the other vertex wud be [-5,-5] and [5.,0]. Now find the length of each side by distance formula and the length will be sqrt125,sqrt125 and sqrt50. Now, draw a perpendicular line from a vertex to the side of length sqrt50. The perp. line wud bisect that line as the. Now u can find the tangents of the angles.

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