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if f(x)={1-x^2, x< or = -1 and 2x+2 , x>-1},then the derivative of f(x) at x= -1 is
LHL of f(x) = 0; RHL of f(x) = 0 so, f(x) is continous
now,
f'(x)= -2x for x<=-1
2 for x>-1
left hand derivative at x= -1 is 2 and right hand derivative is =2
so, LHD=RHD
so f'(x=-1) is = 2.
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