if 2y+x+3=0 touches the circle 5X^2 + 5y^2=k then k= ?

Question

Sanjeev Malik IIT BHU · Answer

x 2 + y 2 =k/5; centre is (0,0). and radius = root(k/5). as line touches circle so distance of line from centre equals the radius, 3/root(2 2 +1 2 )= root(k/5) solving, k= 9

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if 2y+x+3=0 touches the circle 5X^2 + 5y^2=k then k= ?

if 2y+x+3=0 touches the circle 5X^2 + 5y^2=k

then k= ?

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