MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12
        

1680_15271_phy r4.jpg

8 years ago

Answers : (7)

SAGAR SINGH - IIT DELHI
879 Points
							

Dear student,

In case 1:

Yes vapor density will remain same thruoghout the reaction course so it is correct.

In case 2:

Yes option B is very much correct

Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.

All the best.

Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.

Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar  respectively : Click here to download the toolbar..

 

Askiitians Expert

Sagar Singh

B.Tech, IIT Delhi

8 years ago
vikas askiitian expert
509 Points
							

Q-56 ..

rod will behave as chord of circle ... perpendicular distance bw rod &

center of circle can be calculated , let this distance is d ...

 d2 + (L/2)2 = R2                   (by pythegorus theorem)

 d2  = 4-1 = 3

 d = root3

 initially rod was verticle , let bottom most point of sphere  is at 0 potential then

potential of center of mass of rod is mgR  (initially , when rod is verticle)      &

potential of center of mass of rod is mg(R-d)     finally  (when rod is horizontal) ...

 

change in potential energy = change in KE                  (by work energy  theorem)

 

 dKE = IW2/2

 dPE = mgR - (mg(R-d) = mgd

 W = [2mgd/I]1/2                  ...................1

I = Icom + md2 

  = ml2/12 + md2

 l = 2 , d = root3 so

I = m(1/3 + 3) = 10m/3           ..................2

 

putting value of I in eq 1 we get

W = [6root3]1/2

 

option b is correct

8 years ago
aku -- kumar
38 Points
							

dear vikas,

 

i got the first one yes it is correct my option is correct. but second one i'm still getting b, are you getting the same answer.

8 years ago
vikas askiitian expert
509 Points
							

Q=33

 differentiating this eq wrt x using leibnez rule

f1(x) = e-1 (1/2rootx)

dy/dx = 1/2erootx = 1/2ex1/2

dy = dx/2ex1/2

y = x1/2/e + c

at x = 0, y is 0

so , y = x1/2                    .......................1

 or x/e = y2            

this is the eq of parabola ....

option C is correct

approve my ans if u like

8 years ago
vikas askiitian expert
509 Points
							

Q32=>

 f(x) = exsinx           .................1

 

f1(x) = exsinx + excosx      

 

f1(x) = f(x) + excosx        ..............2        (from eq 1)

 

f2(x) = f1(x) + excosx - exsinx     .................3

 

substituting excosx from 2 in 1

 

f2(x) = 2f1(x) - f(x) - exsinx               ..........4

 

substituting exsinx from eq 1 in eq 4

 

f2(x) = 2( f1(x) - f(x) )

 

f2(0) = 2( f1(0) - f(0))

 

in eq 1 & 2 put x = 0 , that will give

 

 f(0) = 0

f1(0) = 1 so

f2(0) = 2

 

in same manner f10(0) = 2*5 = 10

 

option C is correct

 

8 years ago
vikas askiitian expert
509 Points
							

C)focus of parabola is at (1,1) ...

line also passes through this point so this line is also focul chord o this parabola...

for parabola let lengths of two parts of divided by axis is l2,l1 respectively ...

l1 = a(t2+1)

l2 = a(1+1/t2)

harmonic mean is 2

k = 4

8 years ago
vikas askiitian expert
509 Points
							

D) tangent to any ellipse is given

 y = mx + (a2m2+b2)1/2                       

 (y-mx)2 = a2m2 + b2               ................1

let it passes through (h,k) then

(k-mh)2 = a2m2 + b2 

m2(h2-a2) - 2mkh + k2-b2 = 0

from here we get 2 slopes of tangent , let they intersect at 90o ...    (this is assumtion )

m1m2 = -1                   (multiplication of roots = -1)

k2-b2/h2-a2 = -1

k2 + h2 = a2 + b2          .....................2

x2/pi + y2/e = 1           ..............3

a2 = pi , b2 = e

 

now see the given point satisfies the eq 2 so we can surely say that these

tangents intersect at 90o or pi/2

k = 4

 

approve if u like my ans

 

8 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 728 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details