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The equation A2/(x-a)+B2/(x-b)+C2/(x-c)+....+H2/(x-h)=k,has
(a)no real root
(b)at the most one real root
(c) no complex root
(d) at the most 2 complex roots
The option is C , it has all real roots i.e., no complex roots
T o prove this
lets take (p + iq) as a root of above eqn, the for x=(p + iq)
we have
A2/((p + iq)-a) + B2/((p + iq)-b) + ...............+ H2/((p + iq)-h) - k = 0
we can write this eqn in simplified form as
A2.[((p -a)- iq)) / ((p-a)2+q2)] + B2.[((p -b)- iq)) / ((p-b)2+q2)] + ...............+ H2.[((p -h)- iq)) / ((p-h)2+q2)] - k = 0
equating imaginery partson both sides to 0 , we have
q* {( A2 / ((p-a)2+q2)+B2/ ((p-b)2+q2)+ .................+H2 / ((p-h)2+q2)} = 0
so q = 0 [since A2 , B2 ,............etc are all positive ]
hence all roots are REAL
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