how to find the equation of a circle which touches x-axis and its centre (h,k) is given..??

if circle touches x axis then always y coordinate of center is radius of that circle ..

 r = k

eq of circle : (x-h)² + (y-k)² = k²

                  x² + y² - 2xh - 2yk + h² = 0

this is the required eq of circle....

Approved

(X-H)²+(Y-K)²=R²

(H,K) IS CENTRE

TOUCHES X AXIS MEANS X HAS SOME VALUE AND Y =0

THEREFORE  (X-H)²+(-K)²=R²

(X-H)²+K² = R²

IS WHAT I THINK

APPROVE PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ

Approved

since the centre is given u can use the center - radius form of the equation i.e.

(x-h)^2+(Y-k)^2=r^2

where r=k

thnx