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how to find the equation of a circle which touches x-axis and its centre (h,k) is given..??
if circle touches x axis then always y coordinate of center is radius of that circle ..
r = k
eq of circle : (x-h)2 + (y-k)2 = k2
x2 + y2 - 2xh - 2yk + h2 = 0
this is the required eq of circle....
(X-H)2+(Y-K)2=R2
(H,K) IS CENTRE
TOUCHES X AXIS MEANS X HAS SOME VALUE AND Y =0
THEREFORE (X-H)2+(-K)2=R2
(X-H)2+K2 = R2
IS WHAT I THINK
APPROVE PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ
since the centre is given u can use the center - radius form of the equation i.e.
(x-h)^2+(Y-k)^2=r^2
where r=k
thnx
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