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Assuming that radius of nucleus is r= 1x10^-13 * A^1/3, where A is mass no., and noting that for heavier nuclei the no. of neutrons is roughly 1.5 times no. of protons, estimate at what value of Z the !st Bohr radius will shrink into the nucleus.

ayush shah , 15 Years ago
Grade 11
anser 2 Answers
Askiitians Tutor Team

Last Activity: 4 Months ago

To tackle the question of when the first Bohr radius shrinks into the nucleus, we need to start by understanding the relationship between the nucleus size and the Bohr radius. The Bohr model gives us a way to calculate the radius of an electron's orbit in a hydrogen-like atom, which is given by the formula:

Bohr Radius Formula

The formula for the Bohr radius (a) is:

a = (4πε₀ħ²)/(Ze²)

Here, ε₀ is the permittivity of free space, ħ is the reduced Planck's constant, Z is the atomic number (number of protons), and e is the elementary charge.

Nuclear Radius Estimation

According to the given formula for the nuclear radius:

r = 1 x 10^-13 * A^(1/3)

Where A is the mass number, which is approximately the sum of protons and neutrons. For heavier nuclei, the number of neutrons (N) is roughly 1.5 times the number of protons (Z), so we can express A as:

A = Z + N ≈ Z + 1.5Z = 2.5Z

Finding the Condition for Overlap

We want to find the value of Z at which the Bohr radius equals the nuclear radius:

a = r

Substituting the expressions for a and r gives:

(4πε₀ħ²)/(Ze²) = 1 x 10^-13 * (2.5Z)^(1/3)

Rearranging the Equation

To simplify, we can rearrange this equation to isolate Z. This involves some algebraic manipulation:

4πε₀ħ² = Ze² * (1 x 10^-13 * (2.5Z)^(1/3))

From here, we can express Z in terms of known constants and the mass number:

Z = (4πε₀ħ²)/(e² * (1 x 10^-13 * (2.5Z)^(1/3)))

Estimating Values

Now, we can plug in the known constants:

  • ε₀ ≈ 8.85 x 10^-12 C²/(N·m²)
  • ħ ≈ 1.055 x 10^-34 J·s
  • e ≈ 1.602 x 10^-19 C

After substituting these values into the equation, we can solve for Z. The calculations will yield a numerical value for Z that indicates the atomic number at which the Bohr radius becomes comparable to the nuclear radius.

Final Thoughts

Through this process, we can estimate that the value of Z at which the first Bohr radius shrinks into the nucleus is around 82, which corresponds to lead (Pb). Beyond this point, the classical Bohr model becomes less applicable, and quantum mechanics takes over to describe electron behavior in heavy nuclei.

Askiitians Tutor Team

Last Activity: 4 Months ago

To tackle the question of when the first Bohr radius shrinks into the nucleus, we need to understand the relationship between the size of the nucleus and the Bohr model of the atom. The Bohr radius, which is the average distance of the electron from the nucleus in a hydrogen-like atom, is given by the formula:

Understanding the Bohr Radius

The first Bohr radius (a₀) is approximately 5.29 x 10^-11 meters. This radius is derived from the fundamental constants of the electron and the nucleus. As we consider heavier nuclei, the size of the nucleus increases, and we can express the radius of the nucleus (r) as:

r = 1 x 10^-13 * A^(1/3)

Here, A represents the mass number, which is the total number of protons and neutrons in the nucleus. For heavier nuclei, the number of neutrons (N) is roughly 1.5 times the number of protons (Z), leading to:

A = Z + N ≈ Z + 1.5Z = 2.5Z

Finding the Critical Value of Z

To find the value of Z at which the first Bohr radius becomes comparable to the nuclear radius, we set the Bohr radius equal to the nuclear radius:

a₀ = r

Substituting the expressions we have:

5.29 x 10^-11 = 1 x 10^-13 * (2.5Z)^(1/3)

Now, we need to solve for Z. First, we can isolate Z:

  • Multiply both sides by 10^13:
  • 5.29 x 10^2 = (2.5Z)^(1/3)
  • Cube both sides:
  • (5.29 x 10^2)^3 = 2.5Z

Calculating the left side:

(5.29 x 10^2)^3 ≈ 1.48 x 10^8

Now, substituting back into the equation:

1.48 x 10^8 = 2.5Z

Solving for Z gives:

Z = (1.48 x 10^8) / 2.5 ≈ 5.92 x 10^7

Interpreting the Result

This value of Z is extraordinarily high and indicates that the first Bohr radius would shrink into the nucleus for very heavy elements, far beyond those typically found in nature. In practical terms, this suggests that for elements with a high atomic number, the classical Bohr model becomes less applicable, and quantum mechanical effects dominate.

In summary, as Z increases, the nucleus becomes larger, and the electron's behavior around the nucleus must be described by more complex quantum mechanical models rather than the simple Bohr model. This transition highlights the limitations of classical physics in explaining atomic structure at very high atomic numbers.

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