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sir,please help me in solving this question

A 0.1kg mass is suspended frm a wire of negligible mass.the length of wire is 1m and its cross sectional area is 4.9 * 10^-7 m^2.if the mass is pulled a little in the vertically downward direction and released,it performs SHM of angular frequency 140 rad/s.if the young's modulus of the wire is n * 10^9 N/m2, the value of n is....

please explain and solve this integer type question of jee2010.

gowtham raj , 14 Years ago
Grade Upto college level
anser 1 Answers
Chetan Mandayam Nayakar

Last Activity: 14 Years ago

youngs modulus =Fl/Adl, thus F=490ndl, F=kdl(hooke's law), k=490n,ω=√(k/m), 140=√(4900n),

n=4

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