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# The set of values for which x^3+1 greater than or equal to x^2 +x is (ans x greater than or equal to -1)

22 Points
10 years ago

Dear Sudha,

The solution to your euqation is as follows:

x3 + 1 ≥ x2 + x

x3 - x2 - x + 1 ≥ 0

x3 + 1 - x(x +1 ) ≥ 0

(x+1)( x2 -x +1 ) - x(x+1) ≥ 0

Takign x+1 in common,

(x+1)(x2 -x +1 -x) ≥ 0

(x+1)(x2 -2x +1) ≥ 0

(x+1)(x-1)2  ≥ 0

Since (x-1)2 is greater than eual to zero for all values of x ( as (x-1)2 is always postive ),therefore

(x+1)(x-1)2  ≥ 0 will happen when (x+1) ≥ 0

i.e x+1 ≥ 0

x ≥ -1

Solved by : Puneet

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