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solve for x log4log3log2(x3-7x2+14x)

solve for x


log4log3log2(x3-7x2+14x) 

Grade:12

1 Answers

Aman Bansal
592 Points
11 years ago

dear Abdul Yazdan Qadri

log4log3log2(x3 -7x2 +14x) =0

log3log2(x3 -7x2 +14x)=40

log2 (x3 -7x2 +14x)=31

(x-1)(x-2)(x-4)=0

hence x=1,2or 4


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