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question mark

-2

Shubham Gupta , 15 Years ago
Grade 12
anser 1 Answers
Jitender Singh

Last Activity: 10 Years ago

Ans:Hello student, please find answer to your question
-2 < tanx < \sqrt{3}
tanx = \sqrt{3}
x = n\pi + \frac{\pi }{3}
tanx = -2
x = tan^{-1}(-2)
x =- tan^{-1}(2)
x =n\pi - tan^{-1}(2)
\Rightarrow n\pi - tan^{-1}(2)< x< n\pi + \frac{\pi }{3}

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