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Shubham Gupta , 15 Years ago

Grade 12

1 Answers

Jitender Singh

Last Activity: 10 Years ago

Ans:Hello student, please find answer to your question
$-2 < tanx < \sqrt{3}$
$tanx = \sqrt{3}$
$x = n\pi + \frac{\pi }{3}$
$tanx = -2$
$x = tan^{-1}(-2)$
$x =- tan^{-1}(2)$
$x =n\pi - tan^{-1}(2)$
$\Rightarrow n\pi - tan^{-1}(2)< x< n\pi + \frac{\pi }{3}$

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