if[x] denotes the greatest integer less than or equal to x then integral of [1/1+x2]dx in limits from 1 to infinity =

Ans: 1

Sol:

Similarly zero for the next intervals.

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Thanks & Regards

Jitender Singh

IIT Delhi

askIITians Faculty

Ans: 0

There is one minor mistake in the above solution. Sorry about that. When x varies from 1 to 2, then integral part of the 1/(1+x²) should be equal to zero. So the integral value should be zero.

 

Thanks & Regards

Jitender Singh

IIT Delhi

askIITians Faculty