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if[x] denotes the greatest integer less than or equal to x then integral of [1/1+x2]dx in limits from 1 to infinity =
Ans: 1Sol:Similarly zero for the next intervals.Cheers!Thanks & RegardsJitender SinghIIT DelhiaskIITians Faculty
Ans: 0There is one minor mistake in the above solution. Sorry about that. When x varies from 1 to 2, then integral part of the 1/(1+x2) should be equal to zero. So the integral value should be zero. Thanks & RegardsJitender SinghIIT DelhiaskIITians Faculty
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