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`        2kg of ice at -20°C is mixed with 5kg water at 20°C.Then find the amount of water in the mixture `
one year ago

123 Points
```							first of all , let us assume that the system finally goes to 0 degrees celcius as both water and ice are to exist . now, if 5 kg water at 20 C temperature comes to 0 C temperature , then , the heat released                                                                      = mC$\DeltaT$(Change in Temperature)                                                                                = 5X4.18X20=418 ….........................1now similarly , when 2 kg ice comes to 0 degrees celcius , the heat requiered                                                                       =2X2.1X20=84since this heat is less than the heat released , some amount of ice will melt also . latent heat of fusion of ice is 334 j per gramnow, let x gm ice has melted , then , total heat absorbed = 418-84=334=massXlatent heat of fusion                                                                       => 334 = x X 334 THEREFORE , ONLY 1 GRAM ICE HAS MELTED INTO WATER . SO , THE REMAINING AMOUNT OF WATER IN THE MIXTURE IS 5.001 KG OR 5001 GRAMS.
```
one year ago
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• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions