x, y and z are unequal positive numbers. Which of the following relations is possible? (A) cosθ = (x²+y²+z²)/(xy+yz+zx)(B) secθ = (x²+y²+z²)/(xy+yz+zx)(C) sinθ = (x²+y²+z²)/(xy+yz+zx)(D) cosecθ = (xy+yz+zx)/(x²+y²+z²).
Sayantan Garai , 5 Years ago
Grade 10
1 Answers
Vikas TU
Last Activity: 5 Years ago
Dear student
x, y , z is any positive numbers
We know that
Cos Q and SinQ can not be greater than 1
So, A nd C can not be the option because in that case numerator is greater than denominator.
Sec Q = 1/CosQ
which is greater than 1
again Cosec Q can not be less than 1
So, B is the correct ans
Hope this helps
Goos Luck
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