Discuss with Askiitians Tutors> What is iota^iota . I really needed to kn...

What is iota^iota . I really needed to know this so my friend told me that ask the iitians . So i am asking an iitian , hopefully you will answer my question ASAP thanks

Lvanish , 8 Years ago

Grade 11

3 Answers

SAHIL

Last Activity: 8 Years ago

Iota is a complex number with the value of root under -1 , so iota to the power iota is , root under -1 to the power root under -1.

THANKS

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krunal

Last Activity: 8 Years ago

actually the ans is (-pie/2).

here, lets assume that A=i^i.

taking log on both side, we can write> logA =ilogi

logA=ilog(1i)......

logA=i[ log1+logi]...........by logarithm property

logA=I[0+i(PIE/2)]......(ARG OF i=pie by 2)

on soloving we get logA=(-PIE/2)

THEREFORE A=e^(-pie/2)

Umakant biswal

Last Activity: 8 Years ago

@ lvanish
iota is besically a greek letter which is used to define the imaginary part of a complex number
lets say we have an equation x^2 +1 =0
the value of x will be the square root of -1 which is fundamentally not possible .
to solve such equation u need the square root of some negative number ,.
the concept of complex number are introduced for that .
iota is used to denote the square root of -1 .
some books u will find that iota is a number whoose square is -1 ..