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y=(x^4+x^2+1)/(x^2+x+1) and dy/dx=px+q, then find the value of p and q.?

y=(x^4+x^2+1)/(x^2+x+1) and dy/dx=px+q, then find the value of p and q.?
 

Grade:11

1 Answers

Arun
25757 Points
5 years ago
Dear student
 
(x^4+x^2+1)/(x^2+x+1) = (x^2  – x+1)
 
Now we have to differentiate (x^2  – x+1)
 = 2x – 1
 
hence
p = 2
q =  – 1
 
 
Regards
Arun (askIITians forum expert)

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