Grade 11Differential Calculus
y=(x^4+x^2+1)/(x^2+x+1) and dy/dx=px+q, then find the value of p and q.?
y=(x^4+x^2+1)/(x^2+x+1) and dy/dx=px+q, then find the value of p and q.?
1 Answer
Arun
Dear student
(x^4+x^2+1)/(x^2+x+1) = (x^2 – x+1)
Now we have to differentiate (x^2 – x+1)
= 2x – 1
hence
p = 2
q = – 1
Regards
Arun (askIITians forum expert)
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