y=(x^4+x^2+1)/(x^2+x+1) and dy/dx=px+q, then find

Question

y=(x^4+x^2+1)/(x^2+x+1) and dy/dx=px+q, then find the value of p and q.?

Arun · Accepted Answer

Dear student (x^4+x^2+1)/(x^2+x+1) = (x^2– x+1) Now we have to differentiate (x^2– x+1) = 2x – 1 hencep = 2q =– 1RegardsArun (askIITians forum expert)

Differential Calculus> y=(x^4+x^2+1)/(x^2+x+1) and dy/dx=px+q, t...

y=(x^4+x^2+1)/(x^2+x+1) and dy/dx=px+q, then find the value of p and q.?

sadhun , 7 Years ago

Arun

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Differential Calculus> y=(x^4+x^2+1)/(x^2+x+1) and dy/dx=px+q, t...

y=(x^4+x^2+1)/(x^2+x+1) and dy/dx=px+q, then find the value of p and q.?

sadhun , 7 Years ago

Arun

Provide a better Answer & Earn Cool Goodies

LIVE ONLINE CLASSES

Ask a Doubt

Other Related Questions on differential calculus

the diameter of a roller is 84 cm and its length is 120 cm. it takes 500 complete revolution to move once over to level a playground. find the area of the playground in square m?

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