Y=A[x+√x^2-1]^n+B[x-√x^2-1]^n Prove that (X^2-1)y2+xy1=n^2y

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Aditya Gupta · Answer

The question is not clear. Are y2 and y1 derivatives or powers? Kindly mention what these terms represent. Better still, upload a picture of the question.

Md nadim · Answer

Y=A[x+√x^2-1]^n+B[x-√x^2-1]^n Prove that (X^2-1)y2+xy1=n^2y Y2 second difrenciation Y1 first difrenciation

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Y=A[x+√x^2-1]^n+B[x-√x^2-1]^n Prove that (X^2-1)y2+xy1=n^2y

Y=A[x+√x^2-1]^n+B[x-√x^2-1]^n
Prove that
(X^2-1)y2+xy1=n^2y

2 Answers

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Y=A[x+√x^2-1]^n+B[x-√x^2-1]^n Prove that (X^2-1)y2+xy1=n^2y

Y=A[x+√x^2-1]^n+B[x-√x^2-1]^nProve that (X^2-1)y2+xy1=n^2y

2 Answers

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Other Related Questions on Differential Calculus

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Y=A[x+√x^2-1]^n+B[x-√x^2-1]^n
Prove that
(X^2-1)y2+xy1=n^2y