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`        Xy^2(1+x^2) dy+(1+y^2) x=0Find its differential equation by variable separation method. `
8 months ago

Arun
23872 Points
```							y =tan[C- arctan(x)]The original equation is separable, so you should get:Integral of [(1/(1 + y^2))dy] = Integral of [(1/(1 + x^2))dx]which integrates to give:arctan(y) = - arctan(x) + C[where arctan(x) = tan^-1(x)]Thus, on taking the tangent of both sides, we havey =tan[C- arctan(x)]
```
8 months ago
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• 51 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions