Grade 12Differential Calculus
x=acost y=bsint then dsquarey by dxsquare at t=pie/4
x=acost y=bsint then dsquarey by dxsquare at t=pie/4
1 Answer
Arun
Dear student
x^2 / a^2 + y^2 /b^2 = 1
now
2x /a^2 + 2y dy/dx / b^2 = 0
- (x/y ) (b^2 /a^2) = dy/dx
- b^2 / a^2 = y d2y /dx2 + (dy/dx)^2
now find y and dy/dx at t= pi/4
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