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X^2dy/dx=x^2sin3x+c please someone should help me out with this question

X^2dy/dx=x^2sin3x+c please someone should help me out with this question

Grade:6

1 Answers

Arun
25750 Points
6 years ago
Dear Students
 
dy/dx = (x² sin3x + c)/x²
dy/dx = sin 3x + c* x-2
dy = (sin 3x + c* x-2 )dx
On integrating
y = - (cos 3x)/3 - c* x-1 + k
 
Regards
Arun (AskIITians forum expert)

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