Differential Calculus
why do we use exp(-iwt) as a kernel function in fourier transform?
why do we use exp(-iwt) as a kernel function in fourier transform?
1 Answer
Vijay Mukati
Hi, Fourier transform is a special case of the Laplace transform in which real part is zero. Therefore the only term left is imaginary and is equal to -jwt. F-transform is only defired for the stable signals/systems only.
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