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what is the value of

what is the value of

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Grade:12

1 Answers

Harsh Patodia IIT Roorkee
askIITians Faculty 907 Points
7 years ago
This can be solved using expansion of sin-1x and tan-1x which follows

sin^(-1)x=x+1/6x^3+ 3/(40)x^5+5/(112)x^7+(35)/(1152)x^9+...

tan^(-1)x=x - 1/3x^3 + 1/5x^5 – 1/7x^7+...
When you will substitue and put limit you can easily get the answer.



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