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What is the differentiation of tan^-1((1-sinx)/cosx) What is the differentiation of tan^-1((1-sinx)/cosx)
Dear student y = tan^-1 (sin x/2 – cosx/2)^2 / (cosx/2 – sinx/2)(cosx/2 + sinx/2) y = tan^-1 (cos x/2 – sinx/2) / cos x/2 + sinx/2 y = tan^-1 (tan(pi/4 – x/2)) y = pi/4 – x/2 y = – 1 /2
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