Vikas TU
Last Activity: 7 Years ago
Dear Student,
Given f(√π/2)= √(1+1/2)=√3/√2
Now , squaring both sides we get ,
, f(x)^2= 1+Cos^2 x^2
Dwr to x
2f(x).f'(x)= -2Cos x^2 Sin x^2 .2x
Putting value of x in place we get
√3/√2 x f'(x) = -2 x(1/√2)x(1/√2)x √π/2
So, value of f'(x) is. -√π/√6.
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)
