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Differential Calculus> Value of x image is attached...

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Value of x
image is attached

Drake , 11 Years ago

Grade 12

1 Answers

Jitender Singh

Ans:

$[cos^{-1}x]>0$

$f(x) = cos^{-1}x$

$\Rightarrow -1\leq x\leq 1$

$0\leq cos^{-1}x\leq \pi$

$[0]\leq [cos^{-1}x]\leq [\pi]$

$0\leq [cos^{-1}x]\leq 3$

$[cos^{-1}x] =0, 1, 2, 3$

Value of x for:

$[cos^{-1}x] =0$

$\Rightarrow cos1< x\leq 1$

So final solutions is:

$x\in [-1, cos1)$

Thanks & Regards

Jitender Singh

IIT Delhi

askIITians Faculty

Last Activity: 11 Years ago

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