U=F(R,S) and r=x+y , s=x-y show that (∂u/∂x)+(∂u/∂y)=2(∂u/∂r)

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Aditya Gupta · Answer

Write RHS du/dx+du/dy= du/dr*(dr/dx+dr/dy) Now dr/dx= 1 and dr/dy= 1 So RHS= du/dr*(1+1)= 2du/dr= LHS hence proved

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U=F(R,S) and r=x+y , s=x-y show that (∂u/∂x)+(∂u/∂y)=2(∂u/∂r)

U=F(R,S) and r=x+y , s=x-y show that (∂u/∂x)+(∂u/∂y)=2(∂u/∂r)

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U=F(R,S) and r=x+y , s=x-y show that (∂u/∂x)+(∂u/∂y)=2(∂u/∂r)

U=F(R,S) and r=x+y , s=x-y show that (∂u/∂x)+(∂u/∂y)=2(∂u/∂r)

1 Answers

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Other Related Questions on Differential Calculus

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