MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass
        
The value of limit x tend to 0 ((sinx)^1/x + (1/x)^sinx) equals
6 months ago

Answers : (1)

Aditya Gupta
1125 Points
							
obviously limit x tend to 0 (sinx)^1/x=0 because sinx is less than one and when it is raised to power of 1/x (which tends to infinity), it approaches zero.
now, limit x tend to 0 (1/x)^sinx=limit x tend to 0 1/x^sinx= 1/limit x tend to 0 x^sinx
to find limit x tend to 0 x^sinx, take log and we get
sinx*logx=(sinx/x)*x*logx
since sinx/x=1 as x is near zero, so we are left with
xlogx. now put x=1/y so that y tends to infinity.
so limit becomes
-logy/y
apply lhospital rule
-1/y=0 as y tends to inf.
take antilog
L=1
5 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 51 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details