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question mark

The point on the curve y=x√1-x2,-1≤x≤1 at which the tangent is vertical are
A) (-1,1)
B) (-1/√2,1/√2)
C) (0,1)
(More than one can be correct )

Pawan joshi , 7 Years ago
Grade 12th pass
anser 1 Answers
Arun
Dear student
 
dy/dx = -2x^2/ 2 sqrt(1- x^2) + sqrt(1- x^2)
 
dy /dx = (1 – 2 x^2 )/ sqrt (1 – x^2)
 
as the tangent is vertical, hence
 
sqrt (1- x^2) = 0
 
x = ± 1
 
Last Activity: 7 Years ago
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