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Grade: 12th pass
        
The options to the above question are
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1
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none of the above
 
one year ago

Answers : (1)

Aditya Gupta
1715 Points
							
Write it as (sinx-cosx*x^2)/x^2sinx
Now use series expansion of sin and cos
(x-x^3/6+...-x^2 (1-x^2/2+....))/x^3*[x/sinx]
After a bit of manipulation you will see that the terms DON'T cancel out and instead we get smth like
(1+x)/x^2 
So the limit above is plus infinite.
 
one year ago
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