The options to the above question are01¼none of the above
Pavan , 6 Years ago
Grade 12th pass
Differential Calculus> The options to the above question are 0 1...
1 Answers
Aditya Gupta
Last Activity: 6 Years ago
Write it as (sinx-cosx*x^2)/x^2sinx
Now use series expansion of sin and cos
(x-x^3/6+...-x^2 (1-x^2/2+....))/x^3*[x/sinx]
After a bit of manipulation you will see that the terms DON'T cancel out and instead we get smth like
(1+x)/x^2
So the limit above is plus infinite.
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