Khimraj
Last Activity: 7 Years ago
Differentiating curve equation
25x4 – 30x2 + 1 + 2m =0
2m= 30x2 - 25x4 – 1
m =15x2 – (25/2)x4 – 1/2
m(0,-3) = -1/2
So slope of normal at p(0, -3) = -1/m(0,-3) =2
It is also tangent to curve at some points (x,y) then
m(x,y) = 2 =15x2 – (25/2)x4 – ½
So 3 = 30x2 – 25x4
25x4 - 30x2 +3 = 0
Solve this equation for value of x and then put value of x in equation of curve to find value of y.