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the no. of real solutions of e^x=1+sinx is
a)0 b)1 c) 2 d) inf

kuldip singh , 5 Years ago
Grade 12
anser 1 Answers
Aditya Gupta

Last Activity: 5 Years ago

we can easily solve this by considering the graphs of e^x and 1+sinx and then looking at the number of intersections of both graphs. obviously, there would be infinte intersections as e^x is always positive and decreasing.
hence answer is INFINITE solutions.
kindly approve :)

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