The maximum value of (logx)/x is - 2/e
- 1/e
- 1
- e
Please explain it.
The maximum value of (logx)/x is
- 2/e
- 1/e
- 1
- e
Please explain it.
Rakhi Agrawal , 10 Years ago
Grade Select Grade
Differential Calculus> The maximum value of (logx)/x is 2/e 1/e ...
2 Answers
noogler
1/e
let f(x)=logx/x
to get max of f(x)............ fi(x)=0 u get some value of x
substitute it in f(x) u get max value of f(x)
Approved Last Activity: 10 Years ago
Yash Chourasiya
Dear Student
Let f = logx/x
Derivative is
df/dx = (1−logx)/x2
maximum value occurs when derivative is zero.
So⇒ (1 − logx)/x2 = 0
⇒logx = 1
⇒x = e
I hope this answer will help you.
Thanks & Regards
Yash Chourasiya
Let f = logx/x
Derivative is
df/dx = (1−logx)/x2
maximum value occurs when derivative is zero.
So⇒ (1 − logx)/x2 = 0
⇒logx = 1
⇒x = e
I hope this answer will help you.
Thanks & Regards
Yash Chourasiya
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