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Grade 11Differential Calculus

The maximum are of right angle triangle with hypotenuse h is .....?
Options are 1 . h^3/2*sqrt2
2.h^2/2
3.h^2/sqrt2
4.h^2/4

Profile image of Sameeksha
8 Years agoGrade 11
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1 Answer

Profile image of Arun
8 Years ago
Dear Sameeksha
 
Maximum are would be if triangkenis isosceles.
Hence
Side should be h/ \sqrt2.
Hence area of traingle = (1/2) * (h/\sqrt2)*(h/\sqrt2)
= h²/4
 
Option D
 
Regards
Arun (askIITians forum expert)

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