# The maximum are of right angle triangle with hypotenuse h is .....?Options are 1 . h^3/2*sqrt2 2.h^2/2 3.h^2/sqrt24.h^2/4

Arun
25763 Points
4 years ago
Dear Sameeksha

Maximum are would be if triangkenis isosceles.
Hence
Side should be h/ $\sqrt$2.
Hence area of traingle = (1/2) * (h/$\sqrt$2)*(h/$\sqrt$2)
= h²/4

Option D

Regards