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the first derivative of a function (sin2x cos2x cos3x+log22x+3) with respect to x at x= π is 0 1 -1 does not exist
obviously log22x+3= x+3now let f(x)= sin2x cos2x cos3x+log22x+3= sin2x cos2x cos3x+x+3then f’(x)= 2cos2xcos2x cos3x+sin2x*g’(x)+1, where g(x)= cos2x cos3xnow f’(pi)= 2cos2picos2picos3pi+sin2pi*g’(pi)+1= – 2 + 0 + 1= – 1kindly approve :)
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