the domain of the function f(x)={e^sin^-1(logx^2)}^1/2 is: (base 16)

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Arun · Answer

Dear student now the base of log is 16. we can have only problem with sin^-1 expression. hence -1 16 x 2 1/16 2 hence x belongs to [1/4, 4]

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the domain of the function f(x)={e^sin^-1(logx^2)}^1/2 is: (base 16)

the domain of the function f(x)={e^sin^-1(logx^2)}^1/2 is:
(base 16)

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the domain of the function f(x)={e^sin^-1(logx^2)}^1/2 is: (base 16)

the domain of the function f(x)={e^sin^-1(logx^2)}^1/2 is: (base 16)

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the domain of the function f(x)={e^sin^-1(logx^2)}^1/2 is:
(base 16)